# Matplotlib compatibility patch for Pyodide
import matplotlib
if not hasattr(matplotlib.RcParams, "_get"):
matplotlib.RcParams._get = dict.get
Exam Friday January 31th#
Today you’ll make the second exam assignment covering Continuuum mechanics including its prerequisites and/or the first exam assignment covering Buckling including its prerequisites. For more information about the exam see the assessment information in course information
Exam assignment 2 Continuum mechanics#
Your own submission and its grading will be available on exam assignment Continuum mechanics 2 after the exam.
Given is the following structure:
Find the stress state with maximum shear stresses in point \(\text{D}\) and draw the (rotated) stress element for this stress state
Find the principal stresses in point \(\text{D}\) and draw the (rotated) stress element for this stress state.
Draw the required yield stress envelope for Tresca’s yield criterion in the relevant principal stress plane including values.
Solution
In \(\text{D}\) the shear stress \(0\).
Relevant cross-sectional properties are:
\(A = 20250 \text{ mm}^2\)
From top fibre downwards, the normal force centre is at \(70 \text{ mm}\)
\(I_{zz} = 37462500 \text{ mm}^4\)
The normal stress is \(-25 \text{ MPa}\) with no shear stresses.
As this is the only stress, the principal stresses are: \(\sigma_1 = -279 \text{ MPa}\), \(\sigma_2 = \sigma_3 = 0 \text{ MPa}\).
Because of \(\sigma_2 = 0 \text{ MPa}\), the maximum shear stress is \(\cfrac{279}{2} = 139 \text{ MPa}\) at \(45^{\text{o}}\). Or it can be found by rotating the right plane \(\cfrac{1}{4}\pi \text{ rad}\):
\(\sigma_{\bar x \bar x} = -279 \cos \left(\cfrac{1}{4}\pi\right)^2 = -139 \text{ MPa} \)
\(\tau_{\bar x \bar y} = -279 \sin \left(\cfrac{1}{4}\pi\right) \cos \left(\cfrac{1}{4}\pi\right) = 139 \text{ MPa}\)
This can also be found using Mohr’s circle:
The Tresca yield criterion looks as follows:
Exam assignment 1 Buckling#
The exam assignment was provided as shown here
Solution
The solution is shown here